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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Bohrs energy.........
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srujana (3264)

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According to Bohrs theory the electronic energy of  H in nth orbit is given by

En=(-21.76*10-19 J)(1/n2)

Calculate the longest wavelength of light that will be needed to cause this transition.


(Ans: 20.5 *10-7m)

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Nithy (400)

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Hi!
Do specify transition from which orbit to which orbit.

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srujana (3264)

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hi Nithy
tats what the problem is............no info. is given about the transition

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bhuvana89 (1051)

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I THINK THE TRANSITION IS FROM N=2 TO N=1 .......

BUT STILL I'D LIKE TO CONFIRM....

woods are lovely, dark and deep.....
but i have promises to keep....
and miles to go before i sleep....
and miles to go before i sleep....
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srujana (3264)

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longest wavelength or shortest energy is possible only for the transition from 2-1, but the answer dosent tally with the answer given

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ab_batra (31)

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longest wavelenth means shortest energy and so transition is from 2 to 1
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manan (33)

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21.76..... whatever b is given
 
in the question
 
we have to first convert in eV
 
THAT'S COME OUT TO B
 
BETWEEN 10.2 TO 13.6 eV
 
THEREFORE IT
 
CORRESPONDS TO LYMAN
 
SERIES
 
NOW WE KNOW THAT
 
LONGEST WAVELENGTH
 
FOR LYMAN SERIES COME
 
AT TRANSITION n1=1 & n2=2
 
 
 
PLS REPLY IF MY
 
EXPLANATION IS CORRECT
 
 

manan salman khan
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edison (5135)

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Q) According to Bohrs theory the electronic energy of  H in nth orbit is given by

En=(-21.76*10-19 J)(1/n2)

Calculate the longest wavelength of light that will be needed to cause this transition.

Ans) Here longest wavelength is required only when minimum energy is required,
Thus we should consider transition from n = 1 to n = 2
 
So energy change involved is = E2  - E1 = (-21.76*10-19 J)(1/4) - (- 21.76*10-19 J)(1/4)
 
so wavelength =  = hc / (E2  - E1)
 
where h = plankcs constant
 
c = speed of light.
 
Substitute the values to get the results.



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