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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Jul 2007 14:16:37 IST
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The height tap is 5 mts. when the fifth drop was going to fall first drop fall.What is the distance between third drop and flour. if you like question rate me.
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1 Jul 2007 14:23:09 IST
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is the answer 0.9 mtrs
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1 Jul 2007 14:24:45 IST
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is the answer 4.8 mtrs ?
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1 Jul 2007 16:49:08 IST
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Is it 0.8m,if g=10?
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1 Jul 2007 17:43:01 IST
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Is it 0.2
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1 Jul 2007 18:10:18 IST
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I think it is 1.4m. 5=1/2 gt^2 t=1 drops fall at regular intreval. intreval=1/5= .2 s=1/2 gt^2 s4=1/2 *10*.6^2 s3=1/2*10*.8^2 subtracting, ans: 1.4m
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1 Jul 2007 18:41:53 IST
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time taken for the first drop to fall= [2h/g]^1/2 = 1 sec since drops fall uniformly, 5 drops fall in 1 sec... hence 1 drop falls in 1/5 = 0.2 sec so, third drop falls wen t= 0.4 .: the third drop shud have fallen for 1-0.4= 0.6 sec dist covered by 3rd drop= 1/2*g*0.6*0.6 = 1.8 m .: distance of the third drop from the floor= 5-1.8 = 3.2 m hope u got it... thank ya.. Goutham Harsha .K {i find bliss in ignorance ^_^ }
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1 Jul 2007 19:59:27 IST
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Well done kghedriu
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2 Jul 2007 02:16:03 IST
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Good solution kghedriu
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15 Jul 2007 16:49:50 IST
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it is 3.75mt
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