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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Jan 2007 18:56:39 IST
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integrate  (1-t^2)dt
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16 Jan 2007 19:13:54 IST
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t-t^3/3+c
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iitaspirant001@yahoo.com |
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16 Jan 2007 19:21:55 IST
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sorry the question was (1-t)^2dt |
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16 Jan 2007 19:49:20 IST
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answer is t+(t^3)/3-t^2+c
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ADARSH
NITK Surathkal
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16 Jan 2007 20:20:34 IST
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I =  (1-t)2dt
= (1- 2t + t2) dt
= t - t2 + t3/3 + C
where C is constant of integration.
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