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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Jul 2007 08:41:02 IST
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a mixture of CuO and Cu2O contain 88% Cu. calculate the % composition of mixture.
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see one of the flaw in ques is one shud mention percentage by what..here i am solving by percentage by wt...lets coonsider 100gm of mixture and x gm of CuO..so (100-x)gm of other..now since one mole of CuO contains one mole of Cu so tht means x gm of CuO will have x*63.5/(63.5+16) gm of Cu..similarly fr Cu2O it contains (100-x)*2*63.5/(2*63.5 + 16)..now equate it to 88 percent of 100
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a 2nd year IIT DELHI student, doing B.Tech in chemical engineering |
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