IIT JEE , AIEEE Forum - Mathematics , Integral Calculus - Integrate-

BuddyGuy

sin^-1[root(a/a+x)]

puneet

hey

sinA = root(a/a+x)

so cosecA = root(a+x/a)

so cotA = root(x/a)

so we need to intergrate .. cot^-1 [root(x/a)]

Now this is a straight integral

cheers

aansh_c

hy dis 1 is a simple solution

theta=@ ok?

put x=a*tan^2@

dx=2*a*tan@*sec^2@

so d term 2 integrate will be

@*2*a*tan@*sec^2@

den simply use by parts

Ask & Discuss Questions with Community & Experts