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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Jul 2007 12:36:32 IST
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WHY DOES DIPOLE REMAINS STABLE IN SPITE OF THE FACT THAT IT CONTAINS 2 OPPOSITELY CHARGED PARTICLES??WHY SHOULDN'T THEY GET ATTACHED TO EACH OTHER????
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23 Jul 2007 04:10:41 IST
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isn't here anyone who can solve my problem???
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23 Jul 2007 11:10:26 IST
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a dipole is stable though it consists 2 opp charges b'coz they are seperated by a resonable amt of distance to overcome thir repulsive forces actually , dipole is a system which contains 2 opp charges seperated bya distance such that distance of field point is greater than the distance between the opp charges. rate if u find it useful!!!!
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Bad news is that time always flies,
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23 Jul 2007 12:10:59 IST
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Well, dipoles don't exist to a great extent in practical situations. So if you're thinking of two point charges held apart, give up that belief, because that's simply an idealisation. One way of getting close to a dipole, is I guess, to rub the ends of an insulating rod in such a way that both ends get opposite charges. Or you should be looking at the molecular level(the HCl molecule, for instance), where there is inter-electronic repulsion to counter the attractive force.
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23 Jul 2007 16:02:11 IST
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there is an attraction but it is very weak as the particles r of very negligible masses.but when they are brought together centre of
+ve charge overlaps with centre of -ve charge.
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a life above zenith of unrivelled KING
NEERAJ SHARMA |
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23 Jul 2007 22:03:18 IST
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basicaly dipole is a concept and not neccessary that they r seperated in air or vaccume medium dipole can be constructed using a solid rod also . Ofcource there must be atractive force between two opposit charge but they r seperated by some stenghten objec , it can be molecules , stick ,or any solid object whether microscopic or macroscopic.This is the only reason due to which the r not getting collapsed to each other.
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24 Jul 2007 19:32:38 IST
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hi hard core genius.when the dipole lies parallel to the external electric field the angle betw. external electric field and the dipole is 0 so per the equation for work done W=PEcos(THETA), cos(THETA =cos(0).so W=PE and thus is in stable equilibrium
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