IIT JEE , AIEEE Forum - Mathematics , Algebra

a4asd

f(x)=log_3+x(x²-1)

<marquee>find the domain of this function

</marquee>

a4asd

please solve this

a4asd

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pottermania1990

x^2 - 1>0

x^2 > 1

-1>x>1

also x + 3 not equal 0,1

x not equal to -3 ,-2

domain (-infin.,-3) u (-3,-2) u (-2,-1) u (1,infin.)

i think im rite .correct me if im wrong

cheers

rate me if im rite

aravindh_ramaswamy

I want to ask:

y r u using HTML tags here and there??!!??!!

elessar_iitkgp

I would like to add a little to pottermania's solution. It is slightly incorrect.
One more condition must be observed
x+3>0
(As the base of the logarithm must be positive and unequal to unity)
x> -3
The solution then becomes
x

(-3,-2)

(-2,-1)

(1,

)

pottermania1990

i forgot elessar

thanks man

shashiiitian

answer for this should be ====

x =1/2+root 5/2

a4asd

pottermania's is worang

gourav_007

logarithm function will be defined when

x²-1>0 &3+x>0 &3+x

1

i.e (x+1)(x-1)>0 & x>-3 & x

-2

i.e x

(-

,-1)

(1,

) &x>-3&x

-2

so the intersection of these domains is the

ANSWER THAT IS (-3,-2)

(-2,-1)

(1,

)

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