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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Jul 2007 00:09:33 IST
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a trihedral prism with refracting angle 60 provides the least deflection angle 37 in air. find the least deflection angle of that prism in water.
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tejas |
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Let refractive index of material be n. So n = sin((A+da)/2)/sin(A/2) where A is angle of prism = 60 da is angle of least deviation = 37 This gives n
For the case of water (refractive index = 1.33) refractive index of medium is n/1.33. So n/1.33 = sin((A+dw)/2)/sin(A/2) From this solve for dw
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Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi |
this reply: 5 points
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