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![[Post New]](/templates/default/images/icon_minipost_new.gif) 2 Aug 2007 19:24:29 IST
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What is the locus of a point if the sum of the distances of that point from 2 perpendicular lines is 1?? Solution needed
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2 Aug 2007 19:31:45 IST
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Let the two perpendicular lines be x axis and y axis.
Perpendicular distance from x-axis = |y|
Perpendicular distance from y-axis = |x|
Given |x| + |y| = 1
In four quadrants they will form four lines.
x+y = 1
-x+y = 1
x-y = 1
-x-y = 1
They form the sides of a square.
Hence the locus of the point is a square with side root(2).
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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2 Aug 2007 19:46:29 IST
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yes hes correct there.. locus will be a tilted square.
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---------------------------------------------------------------
* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
  
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2 Aug 2007 19:51:32 IST
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thank u ............I have voted ur answers....do tel me how can I earn nickels.............??
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4 Aug 2007 13:23:10 IST
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refer a friend to this site or post articles on community shelf
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* Gaurav Ragtah ( aka Artemis Fowl )
* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)
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