| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Aug 2007 13:19:37 IST
|
|
|
an aeroplane has to go from a point A to point B,500 km away due 30deg east of north.a wind is blowing in direction due north at a speed of 20m/s.the air speed of the plane is 150m/s.find the direction in which the pilot should head the plane to raech point B. i got the answer a month ago but i am not getting it now ANS(SIN INV(I/15))
|
|
|
|
3 Aug 2007 13:24:22 IST
|
|
|
plase try to go every thing using only and only vector laws.it is a very easy que
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
3 Aug 2007 13:30:43 IST
|
|
|
THE ANS IS GETTING COMPLICATED PLZ SOMEONE ANSWER QUICKLY PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
3 Aug 2007 13:46:56 IST
|
|
|
It is simple yaar. Let the angle made by the plane be x degrees with the horizontal. disp in x dirX=250km disp in y dir=Y=250root3 km X=uxt X=15tcosx=250000..(1) and Y=250000root3=150tsinx+20...(2) Two equations --1,2 Two variables-t,x Solve!
|
There is no better feeling in this world than being a winner! |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
3 Aug 2007 15:01:08 IST
|
|
|
PLZ SIR CAN U GIVE ME A DETAILED SOLUTION CAN ANYONE ANSWER QUICKLY AS I HAVE A TEST ON KINEMATICS TOMMOROW.PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
3 Aug 2007 15:13:51 IST
|
|
|
AREEEEEEEE KOI THO JAVAB DHO
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
3 Aug 2007 16:18:36 IST
|
|
|
In the figure , the bigger angle is  =  +30degrees By vector laws, tan 30= 150 sin /20+150cos If u want to find alpha(angle with AB) it can be found. angle with the vertical can also be found. Hope this helps. Nudge me for explanations.
|
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
13 Aug 2007 22:57:04 IST
|
|
|
the logic is keep the velocity in theta such that the resultant of both the velocities will be towards east of north 45 degree .
|
Bhupesh.M |
this reply: 0 points
(with 0
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
14 Aug 2007 09:46:38 IST
|
|
|
it's easy
|
Who says nothing is impossible.
I've been doing nothing for years !!..............
I know KUNG FU KARATE
and 47 other dangerous words.............
|
this reply: 5 points
(with 1
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|
Moderation Team
![[Up]](/templates/default/images/icon_up.gif "[Up]"){kind=icon}
![[Thumb - Untitled.jpg]](/upload/2007/8/3/a43c7840e51d0b7c98acbf93786ef0fd_10483.jpg_thumb)
2
