sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

Moderation Team
 90 chars left    advanced
Ask iit jee aieee pet cbse icse state board experts Expert Question: u gotta answr dis
Forum Index -> Mechanics like the article? email it to a friend.  
Author Message
saurabhkrisna (0)

New kid on the Block

Olaaa!! Perrrfect answer. 0  [0 rates]

saurabhkrisna's Avatar

total posts: 1    
offline Offline
i want to ask that if a body is under free fall then its acc. is constant...........and the mass also ..................therefore the force on the body falling should be also constant....................but ,....then why a man falling from 10th floor dies and a man falling from 2 feet has a very small jerk......
    
sam26kal (91)

Cool goIITian

Olaaa!! Perrrfect answer. 15  [23 rates]

sam26kal's Avatar

total posts: 86    
offline Offline
hey
d acc is ntt constant if u resolve into 2 components
vertical n horizontal den acc along d horizontal is costant
where as along d vertical component it keeps on incresing.. dat it changes dats y a man faaling frm 10 th floor dies wherea frm 10 ft one doesntt
hope dat clears ur dbtt
i think dis cud b d possible ans
plzzzzzzz rate if right n satisfied

brilliant brains may be found at d backbenches or even out of d class
 this reply: 0 points  (with Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
krishna.gopal (2399)

Forum Expert Blazing goIITian

Olaaa!! Perrrfect answer. 381  bad job dude!! I dont approve of this answer! 2  [632 rates]

krishna.gopal's Avatar

total posts: 2940    
offline Offline
When a person falls from 10th floor and dies it is not because of acceleration during the free fall. After free fall when body comes in contact with earth it has to stop suddenly. Now it must come to rest in very small time. In this case acc and orce depends on change in velocity and this change is very large for man falling from 10th floor and that is why he dies

Krishna Gopal Singh
B.Tech Chemical Engg
IIT Delhi 2002
Currently doing PhD from IIT Delhi
 this reply: 2 points  (with Olaaa!! Perrrfect answer.   in 1 votes )   [?]
 
You have to be logged on to rate
  
aaabothra (20)

Hot goIITian

Olaaa!! Perrrfect answer. 2  [7 rates]

aaabothra's Avatar

total posts: 114    
offline Offline
--

TECHNOLOGY IS MY WORLD.
 this reply: 0 points  (with Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
aaabothra (20)

Hot goIITian

Olaaa!! Perrrfect answer. 2  [7 rates]

aaabothra's Avatar

total posts: 114    
offline Offline
--

TECHNOLOGY IS MY WORLD.
 this reply: 0 points  (with Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
waterdemon (4762)

Forum Expert Blazing goIITian

Olaaa!! Perrrfect answer. 872  [1073 rates]

waterdemon's Avatar

total posts: 1032    
offline Offline
See this is simple.
 
The only role the acceleration plays in your case is
 
of increasing the velocity.
 
When the person falls from 10th floor he dies and
 
a the person that falls from 2nd feels a jerk bcoz
 
The height from where the person dies is much more than from where he gets a jerk,
 
F=ma you are correct but
 
s=dv/dt change in velocity wrt time
 
S and dv will vary but dt(for body to stop) will be
the same.
 
mass does not change.
 
when the person falls from 2nd floor he attains not
much velocity. (V2=2gH , as U=0)
 
 
But when the person falls from 10th floor he has
greater velocity than the one falling frm 2nd floor.
 
As H is more.
 
Since when both come at ground the velocity of
both becomes zero in same time interval but in
case of the person falling from 10th floor the change in veloctiy is very high as compared to
the person falling from 2nd floor.
 
So person falling from 10th floor dies whereas
one falling from 2nd feels a small jerk.
 
Hope you understood.
plZ rate me for my efforts.
 
Cheers!!!!!!!!!!!!!

Always available for help !

But Remember Don't hesitate to ask a good Question but
Be damn serious for Questioning a weak one.







<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>


<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>







 this reply: 0 points  (with Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
spideyunlimited (3914)

Moderator

Olaaa!! Perrrfect answer. 656  [973 rates]

spideyunlimited's Avatar

total posts: 2976    
offline Offline
in case of collisions, dont consider the force as the main factor,,, it is the momentum... mv . and as 10th floor is much higher therefore velocity increases much more than that if u fell from 2nd floor thus momentum is greater upon hitting the ground and hence higher impact

---------------------------------------------------------------
* Gaurav Ragtah ( aka Artemis Fowl )

* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)

* Your friendly neighborhood spideyunlimited
 this reply: 0 points  (with Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
spideyunlimited (3914)

Moderator

Olaaa!! Perrrfect answer. 656  [973 rates]

spideyunlimited's Avatar

total posts: 2976    
offline Offline
momentum increases much more when falling from higher height as time of free fall is greater

---------------------------------------------------------------
* Gaurav Ragtah ( aka Artemis Fowl )

* Agent 'G' [sniper] - SD-6 (Alliance of Twelve)

* Your friendly neighborhood spideyunlimited
 this reply: 0 points  (with Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
 
Forum Index -> Mechanics
Go to:   

Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Narayana - Kota , Delhi , Others
Brilliant Tutorials - Class , Crash
Aakash Institute - Medical , Engg
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya