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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Aug 2007 21:24:15 IST
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solve 2[x+2]-[2x+1-1]=2x+1+1
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Aug 2007 21:32:18 IST
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one soln. definitely is x=0
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ameya s,
1 yr
iit bombay.
if you ever want to help me clean my room, go STUDY NOW!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Aug 2007 22:14:29 IST
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Hey, the solution is that it is true for any value of x. Rate me if I'm correct, if not rate me all the same.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Aug 2007 22:24:20 IST
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Hey metal..... the solution is that x is not equal to zero x belongs to Z-{0} rate me if i m right and if wrong than tell me where m wrong
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Aug 2007 08:44:46 IST
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is that (2^x+1-1) in the power???
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two imp facts abt me.................
1)NIGITHA REDDY is never wrong
2)if u feel that i am wrong in any case then...............slap urself n read the 1st fact properly!!!!!!!!!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Aug 2007 08:46:31 IST
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if it is in the power then the sol is x= -1
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two imp facts abt me.................
1)NIGITHA REDDY is never wrong
2)if u feel that i am wrong in any case then...............slap urself n read the 1st fact properly!!!!!!!!!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Aug 2007 22:19:57 IST
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Hey, Nigitha , put x=1. We have 23-[22-1]=8-[3]=5 on the L.H.S and on the R.H.S we have 22+1=5 So,x= -1 is not the only answer. YOU ARE WRONG......!!!!!!!! And Aditya, put x=0 L.H.S. = 22-[2-1]=4-1=3 R.H.S. = 2+1=3 , hence x=0 satisfies the equation. YOU ARE WRONG ADITYA............!!!!!!!!!!!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Aug 2007 13:52:44 IST
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I agree with metal. I solved it myself and the answer is indeed ALL REAL VALUES OF X.
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I like to be myself. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Aug 2007 14:08:45 IST
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this is such an easy question.. X E R ... all real values of x.
as when we solve, in the last step we get 2 ^(x+2) = 2 ^ (x+2)
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- Gaurav Ragtah (spideyunlimited)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Aug 2007 14:09:17 IST
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this is such an easy question.. X E R ... all real values of x.
as when we solve, in the last step we get 2 ^(x+2) = 2 ^ (x+2)
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---------------------------------------------------------------
- Gaurav Ragtah (spideyunlimited)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Aug 2007 22:56:10 IST
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dint ne one notice..........wat i ased bef......
i gave the ans wen (2^x+1-1) is in power.........
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two imp facts abt me.................
1)NIGITHA REDDY is never wrong
2)if u feel that i am wrong in any case then...............slap urself n read the 1st fact properly!!!!!!!!!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Aug 2007 20:37:05 IST
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You must surely be kidding if you think that to be in the power. It's quite clear enough, isn't it??? Stop being IDIOTIC[never mind the six lettered word in block letters]
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Aug 2007 16:59:03 IST
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metal yaar dont be soo rude.. relax :)
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- Gaurav Ragtah (spideyunlimited)
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Aug 2007 20:36:42 IST
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Hey, please don't mind my language. I am sorry if I have hurt anyone. Spidey, I wasn't intentionally rude. That's the way I am, that's the way I speak. I am a bit cynical. Please bear with me. O.K.?????????? SORRY!!!!!!!!!!!! Hey, folks, will you rate me for appologising???? please do rate me,please.....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Aug 2007 20:49:50 IST
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well i do agree with spidey , on solving the problem i get the last step as 2^(x+2)=2^(x+2). [please do rate me.!!!]
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