IIT JEE , AIEEE Forum - Mathematics , Algebra - a tough problem in geometry-help

vinish

Triangle ABC has AC=BC and

ACB=106^o.M is a point inside the triangle such that

MAC=7^oand

MCA=23^o. Find

CMB.

spideyunlimited

we have (solving)
angle angle ABC + angle BAC = 180 - angle 106
as ABC and BAC are angles opp. equal sides they r equal...so
angle ABC = angle BAC = 87

angle BAM = 87 + 7 = 94 .
angle BCM = 106 + 23 = 129
angle ABC = 87
therefore angle CMB = 360 - ( 94 + 129 + 87)
= 50 degrees

*PLZ RATE * . though it was a really easy question :)

jklmn

Since angle ACB=106, and AC=BC, ABC=BAC=37. hOW DID YOU GET IT AS 87?

spideyunlimited

oh damn... i mixed up another question here... yup its 37.

vinish

now please tell me the answer for this question IN DETAIL for I'm not able to understand and tell me the correct answer of angle CMB.

puneet

hey

spidy .. u hav messed up a lot of things .. i do not think ur solution is correct .. infact .. i am not able to do it .. the triangle seems to b well defined and yet ... i donno ..

i am trying it out .. will tell u as i get it ..

cheers

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