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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Aug 2007 22:48:28 IST
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Find domain of (sinx)1/2 + (16-x2)1/2
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11 Aug 2007 22:51:59 IST
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16-x^2>=0
=>x belongs to [-4,4]
sin x>=0
so x belongs to [2n pi, (2n+1)pi]
take common solution
x belongs to [-4,-pi] U [0,pi]
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~ANSHUMAN
I was born intellegent, education ruined me. |
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11 Aug 2007 22:54:35 IST
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For sin x= sinx>0 x  [o,  ] for 16-x2 x>4 so x [0,TI]
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GIVE LIFE THE BEST....srini...
DO OR DIE, OR BETTER NEVER TRY!!
I dont want to be the most intelligent among the ten.i pray the other nine RE fools!???!!!!!!
it doesn't matter if you win... whats important to me is i win!!!!!!!! |
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11 Aug 2007 23:00:55 IST
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the reqd conditions are 16 - x^2 >=0 implies -4 <= x <= 4 sinx >= 0 implies x belongs to [2n pi, 2n pi+pi] but the first condition restricts our domain of sinx>=0 to x = [0, pi] so ans is [-4,4]  [0,pi] ans: [0,pi] cheers! oops didnt c srini's soln. newayz gud work
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12 Aug 2007 00:10:26 IST
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Ans) xE [0,4]
x^2>=16
x E [-4,4]
sinx >=0... thus x is 0 to pi, 2pi tp 3pi, 4pi to 5pi....
x E [ 2 n pi , (2n+1) pi ]
intersection of the two is x E [0,pi]
*PLZ RATE* n joy u too
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- Gaurav Ragtah (spideyunlimited)
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12 Aug 2007 00:12:52 IST
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i cant believe no one else has got the correct answer... people value of pi is 3.14
and @johrianshuman ur intersection is totally wrong
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- Gaurav Ragtah (spideyunlimited)
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12 Aug 2007 00:22:10 IST
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vasanth is correct
gaurav ur wrong
please explain how did u take the intersection
yaar pi is 3.14 which is less than four hence domain will be from [zero to pi]
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"Imagination is more important than knowledge."
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12 Aug 2007 00:29:05 IST
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oh damn ur right.. lagta hai raat ko my mind doesnt think clearly
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- Gaurav Ragtah (spideyunlimited)
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12 Aug 2007 07:47:57 IST
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what about values between -4 and -pi, sin would be +ve there too.
shouldn't the answer be
[-4,-pi]U[0,pi]
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There is no better feeling in this world than being a winner! |
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12 Aug 2007 09:16:04 IST
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arey haan the answer will be [-4,-pi] U [0,pi]
johri_anshuman is correct
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"Imagination is more important than knowledge."
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12 Aug 2007 10:18:41 IST
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Heres the proper explanation
x belongs to [-4,4]
x belongs to [2n pi, (2n+1)pi]
=> x belongs to [-2pi , -pi] U [0 , pi]
Now take common solution
x belongs to [ -4 , -pi] U [0 , pi]
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~ANSHUMAN
I was born intellegent, education ruined me. |
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13 Aug 2007 17:28:31 IST
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yep,, shit ...didnt plot graph n see
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- Gaurav Ragtah (spideyunlimited)
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