IIT JEE , AIEEE Forum - Mathematics , Integral Calculus

swati

give the solution for the diffrential equation:

X^2(Xdx+Ydy)+Y(Xdy-Ydx)=0

where X^2 represents the square of x.

edison

x²(x dx + y dy) + y (x dy - y dx) = 0

or (x dx + y dy) + y (x dy - y dx)/x²= 0

or d (xy) + d (y/x) = 0

or d ( xy + y/x) = 0

or ( xy + y/x) = constant (say C)

or ( xy + y/x) = C

or y = C/(x + 1/x)

or y = Cx/(x+1) which is the required solution.

patel_rhn

5(dy/dx)^2-3(dy/dx)+2=0
please Solve

sricharan

IT IS AN EQUATION SOLVABLE FOR p WHERE p=dy/dx.given is a quadratic in p find the roots of the equation &then solve