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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Aug 2007 12:12:27 IST
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what will be the next three terms of the series 2, 4, 9, 28, 125, 726 ?
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18 Aug 2007 13:30:11 IST
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The next three terms will be 257,4096,6561
the series is 1^2+1,2^2,3^2,3^3+1,5^3,6^3,4^4+1,8^4,9^4
rate me if i am right.
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I like to be myself. |
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19 Aug 2007 12:02:32 IST
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RATE ME IF THIS IS CORRECT!
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20 Aug 2007 18:05:17 IST
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well, i dont agree to the logic of your series. if it is moving in the series of 1^2 + 1 , 2^ 2, 3^2 ,then why again 3^3 +1 & even if it moves in this sequence then next term should be 4^3, 5^3, 5^4+1,6^4, 7^4,7^5+1
& so on.following your sequence we get 216 after 125 but we know that the immediate term after 125 is 726. so, you are wrong.
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20 Aug 2007 22:06:08 IST
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Hey Rajat, u arnt counting stars?????Or r u??
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HOPE U GOT IT... |
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20 Aug 2007 22:34:39 IST
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ankitha is the question correct for sure coz if u say its wrong later a lot of our time will be wasted
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21 Aug 2007 21:30:34 IST
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I don't understand what you say aratrika
see my logic is allright I just made a mistake instead of 4^4+1 it will
be 5^5+1
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21 Aug 2007 21:41:28 IST
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FOLLOW THE GIVEN SEQUENCE ,RAJAT. FOLLOWING UR SEQUENCE WE GET 216 AFTER 125 BUT IT IS GIVEN THAT THE NEXT TERM IS 726.
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21 Aug 2007 21:48:29 IST
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OK I WAS WRONG
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22 Aug 2007 16:17:52 IST
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The sequence is 1+1=2 1x2+2=4 1x2x3+3=9 1x2x3x4+4=28 1x2x3x4x5+5=125 and so on........ similarly continuing we get required terms as 5047, 40328, 362889 plzzz rate me for my answer.
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22 Aug 2007 17:44:11 IST
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well done sachin !
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