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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Aug 2007 20:43:45 IST
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Find the area bounded by the lines
y=mx,
y=mx+1
y=nx
y=nx+1
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God has given you one face, and you
make yourself another.
~William Shakespeare
You were born an original. Don't die a copy.
~John Mason |
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20 Aug 2007 20:52:18 IST
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Well Srujana , I think the answer should be reciprocal of modulus m-n...i.e. I mean 1/ |m-n| .
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Ken
From: UNITED STATES, Green Bay, Wisconsin
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20 Aug 2007 20:53:28 IST
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ans is right, but how??
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God has given you one face, and you
make yourself another.
~William Shakespeare
You were born an original. Don't die a copy.
~John Mason |
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20 Aug 2007 20:55:44 IST
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Solve these lines simultaneously to get the 4 points....these points are forming a quadrilateral ...
Note that it is a parallelogram...
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20 Aug 2007 20:58:15 IST
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one point is (1/m-n , m/m-n)
other is (1/m-n , n/m-n)
but not getting the other two :(
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God has given you one face, and you
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~William Shakespeare
You were born an original. Don't die a copy.
~John Mason |
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y=mx and y=nx intersect at (0,0)
and solve
y=mx+1 and y=nx+1
x=0 and y=1
so points are (0,0) and (0,1)
and those which u have found(i have not checked them)
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20 Aug 2007 21:32:10 IST
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Consider the line y =mx and y = mx + 1 Perpendicular dist. b/w dem = |(1/(m^2 + 1)^1/2)| Now solving y = mx + 1 and y = nx +1, we get (x,y) = (n/m, n+1) Calculate distance 4m origin and multiply it by the perpendicular distance.... Dats it......
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HOPE U GOT IT... |
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20 Aug 2007 21:37:04 IST
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Jatin u have written...
"Now solving y = mx + 1 and y = nx +1,
we get (x,y) = (n/m, n+1)"
please check this coz u are getting wrong answer...
and the figure so formed will not be a rectangle....but it wud be a parallelogram....so u can't just multiply base and perpendicular.
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20 Aug 2007 21:39:17 IST
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yeah u r right.....made a silly mistake .............
thank you everyone
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God has given you one face, and you
make yourself another.
~William Shakespeare
You were born an original. Don't die a copy.
~John Mason |
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20 Aug 2007 21:41:53 IST
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srujana...i was referring to JATIN..and not u!
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20 Aug 2007 21:46:19 IST
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I'm not sure about the calculations, but the logic is perfectly correct..... 1st i find the perpendicular distance between the lines and then the length of the base..... And area of a parallelogram is base * height.... I dont see nethin wrong..... Plz point out, if u're still uncomfortable with the soln.
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20 Aug 2007 21:47:35 IST
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but i think i too made a mistake.........becoz im not getting the right ans that way
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God has given you one face, and you
make yourself another.
~William Shakespeare
You were born an original. Don't die a copy.
~John Mason |
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20 Aug 2007 21:49:16 IST
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oops...sorry..
I read it wrong...ur concept is absolutely correct...(but calculations are wrong)
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20 Aug 2007 21:51:48 IST
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I'm sorry, i got the mistake..... Finding the distance of the origin 4m the point of intersection of the line y = mx + 1 and y = nx +1 will give the length of the diagonal......... The point of intersection must be of the lines y = mx and y = nx +1....... Regrets...
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20 Aug 2007 21:56:23 IST
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But distance b/w origin an |
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