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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Aug 2007 21:21:40 IST
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please read carefully let us take a graph sheet(look at fig 1) now we draw a unit circle on top of the graph sheet(look at fig 2) if any angle is present in quadrant 1 the angle will be between 0 to 90 degrees. in case of any angle cos  =x and sin  =y. sin  =y=0 cos  = x = 1 =0/1=0 but think of cot  = 1/tan  =1/0 ( which is not defined) so why do we say that all the ratios in the first quadrant is positive??
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Aug 2007 21:35:12 IST
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1st quadrant includes all the angles between 0 to 90.........!!!!!!!!!!!!! i dont think 0 is included....................it lies on the X-axis...............!!!!!!!!
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The inevitable truth of life.....everyone in our life is going 2 hurt sooner or later......u just have 2 realise who is worth.....
the PAIN or the PERSON...!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Aug 2007 21:40:02 IST
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nivedh is right
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God has given you one face, and you
make yourself another.
~William Shakespeare
You were born an original. Don't die a copy.
~John Mason |
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Here  = 0 represents the X - axis... It is the line dat separates the halves...... It is not a part of the quadrant..... More specifically speaking, Domain of cot  is R - (n pi)......
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HOPE U GOT IT... |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Aug 2007 22:08:05 IST
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1st quadrant is between 0 and 90. Actually at 0 the quadrant changes and theta=0 separates the quadrants. Similarly for theta=90.
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Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Aug 2007 22:08:28 IST
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i more thing is that in first quadrant tan value increases from 0 to  (90 degrees) but in the second quadrant why the tan value increases from - to 0?? please explain!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Aug 2007 22:15:13 IST
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'coz its discontinuous................ At @ approaching pi/2 from left, cos @ approaches 0 from right or 0+ At @ approaching pi/2 from right, cos @ approaches 0 from left or 0- Hence the discontinuity.......
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HOPE U GOT IT... |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Aug 2007 22:31:51 IST
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but jatin i am still getting confused. just explain more clearly.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Aug 2007 01:24:59 IST
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Dear sinjan.j and All other trigo. lovers. There is a periodic movement in the value of Sin & Cos. From 0 to 360 drgree Sine moves 0 to 1, 1 to 0, 0 to ?1 and than ?1 to 0. Sameway the movement of Cos but with a difference. See the table below for details. | Angle | Movement of Sin | Movement of Cos | Resulting Movement of Tan | | B/w 0 - 90 | + ve (0 to 1) Increasing | + ve ( 1 to 0) Decreasing | + ve | | B/w 90-180 | + ve ( 1 to 0) Decreasing | - ve ( 0 to ?1) Decreasing | - ve | | B/w 180- 270 | - ve ( 0 to ?1) Decreasing | - ve ( -1 to 0) Increasing | + ve | | B/w 270 -360 | - ve ( -1 to 0) Increasing | + ve ( 0 to 1) Increasing | - ve | Due to this the sign of Tan in first quadrant is 0 to but in second quadrant is - to 0 See the detail values: | Angles | SIN | COS | TAN | | 0 | 0.00 | 1.00 | 0.00 | | 15 | 0.26 | 0.97 | 0.27 | | 30 | 0.50 | 0.87 | 0.58 | | 45 | 0.71 | 0.71 | 1.00 | | 60 | 0.87 | 0.50 | 1.73 | | 75 | 0.97 | 0.26 | 3.73 | | 90 | 1.00 | 0.00 | - | | 105 | 0.97 | -0.26 | -3.73 | | 120 | 0.87 | -0.50 | -1.73 | | |