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Ask iit jee aieee pet cbse icse state board experts Expert Question: trigonometric ratios with the help of unit circle
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sinjan.j (574)

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please read carefully
 
let us take a graph sheet(look at fig 1)
 
now we draw a unit circle on top of the graph sheet(look at fig 2)
 
if any angle is present in quadrant 1 the angle will be between 0 to 90 degrees.
 
in case of any angle
cos =x and
sin =y.
 
 
so in case of 0 degrees
sin =y=0
cos  = x = 1
 
therefore tan =sin /cos
                    =0/1=0
 
but think of cot  = 1/tan  =1/0 (which is not defined)
so why do we say that all the ratios in the first quadrant is positive??
 
 
 






    
nivedh_89 (4573)

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1st quadrant includes all the angles between 0 to 90.........!!!!!!!!!!!!!
i dont think 0 is included....................it lies on the X-axis...............!!!!!!!!

The inevitable truth of life.....everyone in our life is going 2 hurt sooner or later......u just have 2 realise who is worth.....

the PAIN or the PERSON...!!!
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srujana (3264)

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nivedh is right

God has given you one face, and you
make yourself another.
~William Shakespeare

You were born an original. Don't die a copy.
~John Mason
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jatinroxx (355)

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Here  = 0 represents the X - axis...
It is the line dat separates the halves......
It is not a part of the quadrant.....
More specifically speaking,
Domain of cot is R - (n pi)......

HOPE U GOT IT...
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iitkgp_bipin (6466)

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1st quadrant is between 0 and 90.
Actually at 0 the quadrant changes and theta=0 separates the quadrants. Similarly for theta=90.

Bipin Kumar Dubey
Chemical Dept.
IIT Kharagpur

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sinjan.j (574)

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i more thing is that
 
in first quadrant tan value increases from 0 to (90 degrees)
 
but in the second quadrant why the tan value increases from -  to 0??
 
please explain!!




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jatinroxx (355)

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'coz its discontinuous................
 
 tan @ = sin@/cos@
 
At @ approaching pi/2 from left, cos @ approaches 0 from right or 0+
 
At @ approaching pi/2 from right, cos @ approaches 0 from left or 0-
 
Hence the discontinuity.......

HOPE U GOT IT...
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sinjan.j (574)

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but jatin i am still getting confused.
 
just explain more clearly.




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avinash.sharma (1189)

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Dear sinjan.j  and All other trigo. lovers.
 
 
There is a periodic movement in the value of Sin & Cos. From 0 to 360 drgree Sine moves 0 to 1, 1 to 0, 0 to ?1 and than ?1 to 0. Sameway the movement of Cos but with a difference. See the table below for details.
 
Angle
Movement of Sin
Movement of Cos
Resulting Movement of Tan
 B/w     0 - 90
+ ve (0 to 1)  Increasing
+ ve ( 1 to 0) Decreasing
+ ve
B/w    90-180
+ ve ( 1 to 0) Decreasing
- ve ( 0 to ?1) Decreasing
- ve
B/w  180- 270
- ve ( 0 to ?1) Decreasing
- ve ( -1 to 0) Increasing
+ ve
B/w  270 -360
- ve ( -1 to 0) Increasing
+ ve ( 0 to 1) Increasing
- ve
 
Due to this the sign of Tan in first quadrant is 0 to  but in second quadrant is -  to 0
 
See the detail values:
 
Angles
SIN
COS
TAN
0
0.00
1.00
0.00
15
0.26
0.97
0.27
30
0.50
0.87
0.58
45
0.71
0.71
1.00
60
0.87
0.50
1.73
75
0.97
0.26
3.73
90
1.00
0.00
-
105
0.97
-0.26
-3.73
120
0.87
-0.50
-1.73