IIT JEE , AIEEE Forum - Physics , Mechanics

anil_direct

I wanted the solution of H C Verma, Fluid Mechanics.

Question No's are 11.

cvramana

The equation for the equilibrium of the metal piece is

N + F = m g ------------------ (1)

Where F is the buoyant force and N the normal reaction.

F = mg x density of the liquid / density of the solid = mg / 8

Therefore

N = mg - F = mg - mg / 8 = 7 mg / 8.

piyu

I wanted the solution of H C Verma, Fluid Mechanics.

Question No's are 23

edison

In equilibrium condition the weight of the cylinder is balanced by force in th spring in upward direction and buoyancy force exerted by the water in upward direction. So we formulate the equation under equilibrium conition as:

mg = kx + V

g

Where, m is mass of the cylinder

since half of the cylinder is dipped in the water so buoyancy force = V

g

here V is half of the volume of water and

is the density of water which is 1000kg/m^3

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