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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Aug 2007 14:09:18 IST
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swsssssssssssssssssssssssssssssssssssssssssssssssssssssssaaaaaaaaaaaaaaaaaaaaaaaaaaaasssss
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26 Aug 2007 14:12:45 IST
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The H.M of the roots of the eqn. (5+  2)x^2 -(4+ 5)x + 8+2 5 = 0 is |
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26 Aug 2007 19:59:43 IST
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let the roots be x1 and x2.
HM = 2 x1x2/x1+x2
x1x2 = product of roots = c/a
x1+x2 = sum of roots = -b/a
HM = -2c/b
=4
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27 Aug 2007 14:39:31 IST
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let the roots be x1 and x2.
HM = 2 x1x2/x1+x2
x1x2 = product of roots = c/a
x1+x2 = sum of roots = -b/a
let the hm be = h
2/h=i/x1+1/x2
so h= 2x1x2/x1+x2= -2c/b
h = 4
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