a point mass starts moving  along x axiswith constant acceleration.the displacement measured from a convenient position,is 2m at time t=0 and is zero at time t=10 s.if the velocity of the particle is momentary zero when t=6s,determine the acceleration a and the velocity v when t=10s

 

 

 

hey shubham.....my ans. is this..plzzz check this out and correct me if m wrong anywhere.....

     the body is moving along x-axis and after some time the displ. is zero  so the point of view is also on x-axis....the body is moving witrh accl. and velocity is zero at t=6  therefore it is moving with retardation but it reaches the point of view at t=10 so the point of view is behind the initial point of the body.. so

 0=6a+u...........................................................where u is the initial velocity and a is the retardation.

==> a= -u/6

but  10u + 50a=2

==> -60a+50a=2

==> -10a=2 ==> a= -0.2m/s2  therefore u=1.2......velocity at t=10 = u + at = 1.2-10(0.2)=1.2-= = -0.8 = 0.8m/s towards the point of view..

if u find it useful plzzz rate.. :)