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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Sep 2007 17:42:57 IST
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if tanA=kcotB then
cos(A-B)
-----------------=
cos(A+B)
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write k=tanA/cotB
use componendo-dividendo
1+k/1-k= tanA+cotB/cotB-tanA
= sinAsinB + cosAcosB/ cosAcosB-sinAsinB
=cos(A-B)/ cos(A+B)
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17 Sep 2007 18:01:49 IST
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Given
tanA=kcotB
Sin A / cos A = k cos B / sin B
cos A cos B / sin A sin B = 1/ k
( cos A cos B + sin A sin B ) / ( cos A cos B - sin A sin B ) = ( 1+ k ) / ( 1- k )
cos ( A - B ) / cos ( A + B ) = ( 1+ k ) / ( 1- k )
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it is not important where u stand, but in which direction u are moving |
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