IIT JEE , AIEEE Forum - Physics , Mechanics

magiclko

wat exactly is meant by radius of curvature of a particle moving in a parabolic path??? n how to solve for it???

kusum

it means that at that instant if a prticle at that oint was in a circle what would have been its radius

kusum

ok to answer how to find it.at that instant at that pt of the parabolic path utake the velocity along the tangent and then use
centripetla force = centrifugal force.

where both of them to be taken along the normal at that pt.this info will help u to solve a ny ques .hope im clear

magiclko

thanx

kusum

don mention.y dont u try ur first prob keepin thes basi.s

shakirshafi12

radius of curvature=ds/dQ
that is rate of change of path wrt to the rate of chane of angle of slope
dy/dx=tanQ here
and ds=sqroot((dx)^2+(dy)^2)
in shanti narayan they have discussed it in gr8 detail

bhupesh

Dear

Get the value of x coordinate of the object for any time "t" and y coordinate at any time "t "

xi+yj is the vector form of radius of curvature

I belive you got the idea of radius of cuvature

Ask & Discuss Questions with Community & Experts