IIT JEE , AIEEE Forum - Physics , Mechanics

losky

A body starts bslipping down an incline and moves half meter in half seconds how long will it take to move the next half meter.

iitkgp_bipin

Use s = ut + (1/2)at² = (1/2)at²

At t₁=1/2, s=1/2 :

1/2 = u(1/2) + (1/2)a(1/2)²

a = 4 (for u=0)

When s=1 :

1 = ut₂ + (1/2)at₂²

t₂² = 2/a = 2/4 = 1/2

t₂ = 1/

2

Hence time taken to move next 1/2 metre = t₂ - t₁ = 1/

2 - 1/2 sec

loveshah

let the mass of the body be m, and angle of inclination be theta.

ignoring friction,

mg.sin(theta) = m.a

a=g sin(the.)

1/2= 0 + 1/2 .gsin(theta) .(1/2)^2

= sin(theta) = 4/10

= a= 4

v ( after have second) = (2*4*1/2) ^ 1/2

v= 2

now

1/2 = 2t + 2t^2

t= 0.21 seconds

Ignore the negative value in quad. since time cant be -ve.

Plz. rate me!!!

lonewolf07

gr8 work

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