sign up I login
 advanced
refer a friend - earn nickels!!

Ask & Discuss Questions with Community & Experts

 Moderation Team
 90 chars left    advanced
Ask iit jee aieee pet cbse icse state board community Community Discussion Question: challenge!! do it in less than 10 steps
Forum Index -> Trignometry like the article? email it to a friend.  
Author Message
[Post New]26 Sep 2007 15:17:48 IST
    Subject: challenge!! do it in less than 10 steps
[Up] View Post
manoj_babu (28)

Cool goIITian

Olaaa!! Perrrfect answer. 4  [8 rates]
manoj_babu's Avatar
total posts: 82    
offline Offline
p.t sec6x/cosec2x + sec18x/cosec6x + sec54x/cosec18x = 1/2 [tan54x - tan2x]
    
[Post New]26 Sep 2007 20:58:57 IST
    Subject: challenge!! do it in less than 10 steps
[Up] View Post
sankalpraj (0)

New kid on the Block

Olaaa!! Perrrfect answer. 0  [0 rates]
sankalpraj's Avatar
total posts: 23    
offline Offline
dude i think v have to take sec/cosec as cot u may get the answer.....and then convert it to tan....
 this reply: 0 points  (with 0 Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
[Post New]27 Sep 2007 19:01:27 IST
    Subject: Re:challenge!! do it in less than 10 steps
[Up] View Post
manoj_babu (28)

Cool goIITian

Olaaa!! Perrrfect answer. 4  [8 rates]
manoj_babu's Avatar
total posts: 82    
offline Offline
hey the num n denominator r not defined on the same angle so its wrong.v can get tan 2x as factor in 1st term n tan 54 as a factor in 3rd term n v have to split the mid term so dat we get the LHS but indeed it is a 20 step answer
 this reply: 0 points  (with 0 Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
[Post New]5 Oct 2007 18:39:44 IST
    Subject: Re:challenge!! do it in less than 10 steps
[Up] View Post
manoj_babu (28)

Cool goIITian

Olaaa!! Perrrfect answer. 4  [8 rates]
manoj_babu's Avatar
total posts: 82    
offline Offline
s2x/c6x + s6x/c18x + s18x/c54x
2s2x.c2x/2c6x.c2x +..........................
s4x/2c6x.c2x+.....................
s(6-2)x/2c6x.c2x +.................
1/2[s6x.c2x - c6x.s2x]/c6x.c2x +.........
1/2[t6x-t2x] +............................
lll ly s6x/c18x =1/2[t18x-t6x] n s18x/c54x=1/2[t54x - t18x]
=> 1/2[t6x - t2x + t18x - t6x + t54x - t18x]
=>1/2[t54x- t2x]
thus the ans
 
 this reply: 0 points  (with 0 Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
[Post New]5 Oct 2007 18:40:52 IST
    Subject: challenge!! do it in less than 10 steps
[Up] View Post
manoj_babu (28)

Cool goIITian

Olaaa!! Perrrfect answer. 4  [8 rates]
manoj_babu's Avatar
total posts: 82    
offline Offline
rate me if u satisfied
 this reply: 0 points  (with 0 Olaaa!! Perrrfect answer.   in 0 votes )   [?]
 
You have to be logged on to rate
  
 
Forum Index -> Trignometry
Go to:   

 Aakash Institute IIT/ AIEEE/ Medical Crash Course
Name  
E-mail  
Phone  
Mobile  
** Hurry. Exclusive goIIT Offer. Limited Seats Only!
available in: New Delhi, Amritsar, Bhatinda, Bokaro, Chandigarj, Dehradun, Guwhati, Hyderabad, Indore, Jaipur, Kanpur, Karnal, Kolkata, Kota, Lucknow, Ludhiana, Mumbai, Noida, Patiala, Patna, Pune, Ranchi, Varanasi
Top Offers for goIITians
Correspondence Courses
Brilliant Tutorials
Narayana Institute
Aakash Institute
Classroom/Crash Courses
Aakash-IITJEE : AIEEE
Aakash-IITJEE : DCE
Aakash-IITJEE : MHTCET
Aakash Institute : AIPMT
Online Test Series
Brilliant Tutorials
Narayana Institute
Aakash Institute
Mahesh Tutorials
AMITY      Sri Chaitanya