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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Oct 2007 21:25:56 IST
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tell me the
graph of ...
y = sin(x) / sin(x)
it's challenge...
plzzz see m article on one topic of topic of IITJEE..
http://www.goiit.com/posts/list/community-shelf-formulae-28364.htm
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this is just the graph of y = 1 except at points where x is such that sin x = 0.
x = n.pi at all other points graph is defined and is the graph of y = 1 .. at x = n pi however graph will break
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- Gaurav Ragtah (spideyunlimited)
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10 Oct 2007 00:01:03 IST
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25 Oct 2007 14:59:44 IST
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noooooooooo . the value of x changes . suppose x is 45 so at rhs we will get sin1 that is 90 degree.
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2 Nov 2007 18:35:05 IST
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hey viv u r absolutely correct
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5 Dec 2007 15:00:52 IST
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PLZZZZZ HELP
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5 Dec 2007 15:17:00 IST
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dude my answer is correct.. graph is just as viv has drawn except that the points will not be included where sin x becomes 0 as sin x is in denominator.
Here everyone makes a mistake of just cancelling sin x / xin x and making it one.. we can only cancel sin x in numerator and denominator if it is not equal to 0.. remember?basic rule of math.
hence graph breaks at 0, pi, 2pi, 3pi, 4pi etc.
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- Gaurav Ragtah (spideyunlimited)
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5 Dec 2007 18:13:21 IST
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Yes, spidey is right. The graph is not defined when x takes values that are integral multiples of pi or when it is zero
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Will nip in at times to solve problems :)
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8 Dec 2007 22:33:54 IST
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The guys are correct. The graph will be parallel to the x-axis at a distance of 1 unit above it.
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<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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