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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Oct 2007 08:55:11 IST
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plz help me with the ans The percentage ionic character of a compound AB is 20. Its dipole moment in 1.2 D . The bond length in metres is: (a) 1.2 * 10-10 (b)1.25 * 10 -8 (c)25 * 1010 (d) 2*10-10
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SiNcY... |
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20 Oct 2007 12:56:21 IST
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option b is correct answer
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2 Nov 2007 22:32:58 IST
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plzzz explain how??
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SiNcY... |
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7 Nov 2007 14:21:21 IST
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B is the correct answer!
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DO THE BEST AND HOPE FOR THE BEST!!
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10 Nov 2007 11:44:23 IST
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%ionic character=dipole (observed) --------------------------- dipole(theoretical) 20=1.2 ----- x=.06 .0 6=e*d x e=4.8 d=.06 ---- 4.8 -8 d=.0125ang=1.2*10m
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13 Nov 2007 12:23:38 IST
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perfect solution 988
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17 Nov 2007 13:10:47 IST
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Correct answer is 'a'. 20 = (1.2*3.34*10-10*100)/(1.6*10-19*d) by this calculation find out your required answer.
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I like to solve the tough problems, because nothing is tough.
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19 Nov 2007 12:28:44 IST
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it will b 1.5x10^19 decimetres 20\100=1.2\e x l
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