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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Feb 2007 21:27:14 IST
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Hey all , for most of the surfaces used in daily life , the friction cofficient is less than 1 . Is it always necessary that the friction cofficient is less than one ?? If yes , then why ? And if no ,then what can be its maximum value ?
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Umang |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 6 Feb 2007 21:49:02 IST
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it is not necessary...tht da coeff.. of friction shud alwayz be less dan one..!! when ever we polish things we reduce da friction provided by dat surface. but wen we superpolish dat surface..we actually increase da friction to such a limit dat..da coeff of friction is greater dan one..!! polishin-- coeff.....less dan one.. super polishin-- coeff..mite be more dan one..!
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MaYuR.......
ne TimE....ne WheR..!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Feb 2007 20:55:29 IST
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Hey mayur , what u said is right . Also , I found in a book that value of friction's cofficient generally lies between 0.05 and 1.5. Anyways , thnks for giving the answer !!!
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Umang |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 8 Feb 2007 22:49:16 IST
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N (Normal Contact Force) lamda | / | / | / F___________|/____________f (frictional force) A A is the object F is the applied force, so the frictional force would be in opp. dir. as shown the oblic line is the resultant of 'N' and 'f' the angle make by it with N is known as the angle of repose, the friction coiff. is given by tan(angle of repose) ie tan(lamda)
as this angle lies between 0 - 90 (degrees) the codomain of the tan function is 0 - infinity so the friction coiff. can have any value from 0-infinity
thus it can be very well seen that the coiff. would be between 0-1 (as in most cases) the angle of repose (lamda) is between 0-45(degrees)
it is worthy to note that the friction coiff. would be infinity when the angle is 90(degrees) ie. the body does not slide even when the inclination is 90(degrees)
i hope this has answered ur query....
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Feb 2007 15:28:56 IST
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Hey swaroop , I couldn't understand the figure drawn by you !!! Pls explain !!!!!
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Umang |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Feb 2007 15:43:02 IST
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see umang
i ll draw the fig again
the explaination is right
(normal force)
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|/______________ (frictional force)
the line in between shows the resultant force
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Feb 2007 15:47:34 IST
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Hey ! What does that '/'es represent ??? Basically , what are u trying to show ?
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Umang |
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