IIT JEE , AIEEE Forum - Physics , General

siddhanthsharma

Suppose a quantity x can be dimensionally represented in terms of M,L,T is [x]=M^aL^bT^{c
The quantity of mass-
a.can always be dimensionally represented in terms of L,T and X
b.can neveer be dimensionally represented in terms of L,T,X
c. May be represented in terms of L,T and x if a=0
d.May be represented in terms of L,T and x if a is not equal to 0}

mudit_d_best

siddharth the ans should be 'd'. because if a=0 then mass can not be represented by l,t,x as x does not have any term of mass.

Prabhuling

hi
is the ans (d)

uday_zingtudor

yes the answer is d

siddhanth, now u can understand from this question that in IIT the questions are from the basics

they confuse among the basics

so one must be perfect with the basics to crack IIT

kghedriu

First of all, for a physical quantity to exist, in this case, a shouldnot be zero. Hence, d should be correct.

edison

Ofcourse, to express or reperesent a physical quantity by means of some

dimensional equation or otherwise its existence in the equation is necessary

and sufficient condition. Thus M can be expressed in terms of x, L and T

provided a is not equal to ZERO. So 'd' is the correct option.

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