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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Nov 2007 19:29:18 IST
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Triangle ABC is isosceles with base AC. Points P and Q are respectively in BC and AB such that AC=AP=PQ=QB. Find  B in degrees. (Ans: 180/7)
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Its an easy question. Let  1=@ Then  3=@ (AC=AP) Now as AB=AC,  1=  (2+4) = @  2=180-2@ But as AP=AQ, Now  5=540-6@ (Sum of angles in a triangle =180) As QP=QB, Solving we get, @=540/7 Therefore  B=180/7 Rate me if satisfied, Nudge me if not understood.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Dec 2007 02:02:05 IST
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Tarin is right. But instead of putting in numbers, it is always advisable to put in terms of points. I mean, instead of writing 6, write AQP. That always keeps the solution clean.
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Satyaram B V,
General Secretary, Mandakini Hostel,
IIT Madras |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 11 Dec 2007 13:24:06 IST
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Yes, i understood.
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