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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Feb 2007 09:24:01 IST
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Q1) An orbital can have a maximum of 2electrons. Suppose orbitals have 3electrons each(although it's impossible; clockwise & anticlockwise spin would get disturbed and much more) but then too, what would be the number of groups in the periodic table in this condition.
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@seth |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Feb 2007 15:02:51 IST
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is this a factual question or just something u though on ur way back from skool ?.....good question though ......ill think about it
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Sometimes One Dream Is Enough To Light Up The Entire October Sky....
First Year Mechanical Engineering
Veermata Jijabai Technological Institute |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Feb 2007 22:30:10 IST
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anurag,
u doubt is true but actually its just impossible for a orbital to have 3 electrons.
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I HEAR.........I FORGET
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 10 Feb 2007 22:34:24 IST
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48
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 12 Feb 2007 21:12:54 IST
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Hey dude ! I hope u dont mind explaining the answer !!!!!
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Umang |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Feb 2007 16:30:30 IST
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I thought the answer myself. In the s block of Periodic table, due to an increase in an e- , it would now have 3 groups, i.e. maximum e- = 1s3 thus groups in s-block=3 In the d-block there are 5 orbitals and hence increment in no. of e- =5. i.e. max. e- = 5d15 thus groups added=5. thus total groups in d-block=10+5=15. In the p-block there are 3 orbitals and hence increment in no. of e- = 3 i.e. max. e- = 6p9 thus groups added=3 thus total groups in p-block = 6+3=9 to talk of f-block would be a foolish thing. Hence, Total groups in Periodic table with each orbital having three e- = 3(s-block) + 15(d-block) + 9(p-block) =27 Hence according to my analysis the answer must be 27, if I'm wrong somewhere plz let me know.
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@seth |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Feb 2007 20:33:58 IST
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Hey anurag , yes , I also got 27 as the answer . My approach is just as yours . I dont think the answer is wrong !!!
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Umang |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Feb 2007 15:11:08 IST
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Happy ?????
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Umang |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Feb 2007 09:02:49 IST
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If there be three electrons in one orbital, then the no. of groups would be 6
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Lecturar, Organic Chemistry |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Feb 2007 11:00:29 IST
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Smriti Mam, Please explain the way you thought it to be 6 groups.
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@seth |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Feb 2007 12:41:39 IST
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Hey Anurag, according to your calculation, there is an overall increase in the total number of electrons, ie, there is an increase in the total number of elements known. What I have done is , adjusted the same electrons , three in one orbital, keeping the number of elements same.So if there would be three electrons in one orbital, the no. of groups will shrink.
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Lecturar, Organic Chemistry |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Feb 2007 23:02:47 IST
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Well, the number of groups would be 12 not 6.
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Lecturar, Organic Chemistry |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Feb 2007 23:32:17 IST
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Smriti Mam, Still I didn't get through your explanation, plz explain a bit more.
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@seth |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 18 Feb 2007 19:25:59 IST
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Smriti mam , I hav understood what u hav done , but am not getting how u did it . Pls explain !!!!!!! Thank you !
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Umang |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 20 Feb 2007 12:40:51 IST
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