IIT JEE , AIEEE Forum - Mathematics , Integral Calculus - very easy ques (plzzz solve) rates assured

losky

find integration of the following wrt X

(sin^3x + cos^3x)/(sin^2x cos^2x)

I am very new at integration

plz tell me the general things to be kept in mind while solving integration!!!!!plzzzzzzzzz

aditi_g

take both the terms separately...
sin x/cos^2x + cos x/ sin^2x
=now for the first part u take cos x = t
and thn for the second part u take sin x = t...
and in both cases u have their derivatives in trhe numerator...
i hope now u will be able to solve it
the answer will be
sec x - cosec x
rate me if it helps u

sowjanya_reddygudipati

no need for going ny substituation u can directly use

_{[ ]}

^{[ ]} sinx/cos2x=_{[ ]}

^{[ ]} tanxsecx=secx

_{[ ]}

^{[ ]} cosx/sin2x=_{[ ]}

^{[ ]} cotxcosecx=cosecx

Ask & Discuss Questions with Community & Experts