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tarinbansal (3903)

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In the figure a square is given with each side=1 unit.
Four points A,B,C,D are taken arbritrarily on the 4 sides of the square and a quadrilateral is formed by joining them with sede lengths a,b,c,d.
 
Find the minimum value of a2 + b2 + c2 + d2 .
Will be posting solution tomorrow.
Till then give the best solutions to win salutes.
 
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tarinbansal (3903)

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Rate me if you think the question was useful and challenging.

The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.

It is during our darkest moments that we must focus to see the light.

Check out my blog at:
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Posts:
Can marks really judge a student??
Some myths about Chemical Engineering.
(A must see for every student)

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rajatsen91 (817)

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( a^2 + b^2 + c^2 + d^2)/4>=(abcd)^1/2
this min is reached when a=b=c=d
when this happens, then a=b=c=d = 1/(2)^1/2
so min value of a^2 + b^2 + c^2 + d^2 is 4*1/2 = 2

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tarinbansal (3903)

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Rajat,
your answer is right but the solution not satisfactory.
How can you prove that min is reached when a=b=c=d?

The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.

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Can marks really judge a student??
Some myths about Chemical Engineering.
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