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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Dec 2007 22:01:42 IST
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Please answer the following question for me........ Two particles of mass 1 kg and 2 kg respectively are initailly 10 m apart. At time t=0, they start moving towards each other with uniform speeds 2m/s and 1 m/s respectively. Find the displacement of their centre of mass at t=1s.
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zero
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Dec 2007 22:10:25 IST
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Can u give me a detailed solution please?????
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Dec 2007 22:15:04 IST
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rc.o.m =m1r1+m2 r2 /m1+m2 as we are considering displacement r1= 2 ,r2 =-1 ...put the values and get the desired answer
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Dec 2007 22:17:39 IST
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see first find the velocity of centre of mass by using m1v1 + m2v2/m1+m2 ...since they r moving towards each other velocities r in opp direction ... therefore velocity of centre of mass will be 1x2 - 2x 1/ 2+1 =0....since velocity of centre of mass is zero hence displacement will be 0.....nudge me if u hv any doubt
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Dec 2007 22:18:48 IST
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Vcm = m1v1 + m2V2/m1+m2 = 1*2 - 2*1/3 { particles are moving towards eachother so one with positive sign and other with - sign)
Vcm = 0
thus centre of mass remains at rest always
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 4 Dec 2007 22:24:39 IST
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initially m1u1 = m2u2 hence centre of mass is at rest and will be at rest after collision too.
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- Gaurav Ragtah (spideyunlimited)
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