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![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Dec 2007 20:33:43 IST
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DOUBT IN WURTZ REACTION CLICK ON THE PICTURE TO SEE THE QUESTION MORE CLEARLY.
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16 Dec 2007 21:18:44 IST
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is it [iv]....
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"Nenenthedhavano naake teleedu"
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16 Dec 2007 21:36:08 IST
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It should be 1 and 4
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Anyone who has never made a mistake has never tried anything new
You can never solve a problem on the level on which it was created.
When you are courting a nice girl an hour seems like a second. When you sit on a red-hot cinder a second seems like an hour. That's relativity
Purpose of solving a problem is not simply to get the answer(the answer is only an evidence) but to develop your thinking ability |
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16 Dec 2007 21:38:30 IST
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In wurtz reaction only even number carbon containing alkanes can be prepared
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Anyone who has never made a mistake has never tried anything new
You can never solve a problem on the level on which it was created.
When you are courting a nice girl an hour seems like a second. When you sit on a red-hot cinder a second seems like an hour. That's relativity
Purpose of solving a problem is not simply to get the answer(the answer is only an evidence) but to develop your thinking ability |
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16 Dec 2007 21:48:03 IST
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IT SHOULD BE 2&4.
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17 Dec 2007 18:16:36 IST
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It should be only (ii) becoz isme hi even no of carbon atoms hain bas.
(iv) nahi hona chahiye becoz usme the no of carbons is 7 and from wurtz reaction, we can prepare only those alkanes which have even no of carbon atoms.
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but odd can be made..(impure).....real problem is 3 degree alkyls...they tend to form alkenes by disproportionation...
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Don't Dream ..Do the dream...
Rock On ....
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18 Dec 2007 18:06:59 IST
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only 2 can be prepared i think
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its not just about hard work;its how smart you work. |
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18 Dec 2007 18:22:30 IST
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but i think that symmetrical breaking should be possible so only 4 , I guess....
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21 Dec 2007 17:21:54 IST
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pleaseeeeeeeee
helpppppppp everybody is giving different answer.
i think that a symmetrical structure is necessary also and that is not in (ii)
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21 Dec 2007 19:36:03 IST
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it is possible because when we use two different alkanesthen cross product will be the major one .......so iv may be correct.....
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"Nenenthedhavano naake teleedu"
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2 Jan 2008 15:28:09 IST
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Hey the answer is that only (ii) can be prepared by wurtz reaction as it has even number of atoms and also it is symmetric. So I think u got the answer!
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