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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 21:06:52 IST
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Can U please tell me what is Inert Pair Effect & catenation? Rates assured.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 21:21:51 IST
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There's nothing surprising about the normal Group oxidation state of +4 for the elementzzz in group 4.
All of the elements in the group have the outer electronic structure ns2npx1npy1, where n varies from 2 (for carbon) to 6 (for lead). The oxidation state of +4 is where all these outer electrons are directly involved in the bonding.
As you get closer to the bottom of the Group, there is an increasing tendency for the s2 pair not to be used in the bonding. This is often known as the inert pair effect - and is dominant in lead chemistry.
However, just giving it a name like "inert pair effect" explains nothing. You need to look at two different explanations depending on whether you are talking about the formation of ionic or covalent bonds.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 21:27:19 IST
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Carbon is unique among the elements in the almost infinite capacity of its atoms to bond to each other in long chains, a process called catenation. This characteristic reflects the strength of the bond between adjacent carbon atoms in the molecule, both in relationship to similar bonds involving other elements of the carbon family and in relationship?.....!!!!!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 21:28:26 IST
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Actually my real doubt is that in Group 15, the stability of +5 oxi states decreases and that of +3 oxi states increases down the group due to INERT PAIR EFFECT. This statement is given in NCERT. Now please explain INERT PAIR EFFECT in this context. And what role does it play here?
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 21:48:28 IST
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Nivedh, please help me here also!!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 21:57:38 IST
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inert pair effect is nothing put the inability of s electrons to participate in the reaction. s electrons are not able to participate bcoz of strong hold of nucleus (high penetration effect) or por shielding effect of electrons therefore +3 state stability will be in the order Bi>Sb>As and vice-versa for +5 stability more big the atom more poor the shielding effect... catenation is nothing but the property of atom to form giant structures rate me if dis infrmation is useful
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 22:06:53 IST
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Can U please explain how bigger atoms have poor sheilding effect?
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 22:13:21 IST
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as the d or f electrons are situated very far frm each other they give the nucleus to strengthen their hold on the s-electrons and as s electrons show high penetrating effect ie they prefer to live near the nucleus the hold of nucleus on 6s electrons is considerable... plz rate if helped
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 22:22:59 IST
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U said earlier that as we go down the group the hold of nucleus on s electrons increases but the nucleus' hold on 4s electrons will be more than that in 6s, hence it should decrease on going down the group.
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Check out my blog at:
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 22:32:20 IST
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naaaaaaaa....... as we go down the no. of f and d electrons will increase and so will the nuclear charge...... u've misread my previous one
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PROGRESS ISN'T MADE BY EARLY RISERS OR HARD WORKERS, BUT BY LAZY PEOPLE TRYING TO FIND EASIER WAY TO DO THE SAME.....SO BE LAZZZZYY!!!! |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 22:37:56 IST
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Yaar, just now Nivedh told me in my another post that oxi state is nothing but just a number calculated when an element has formed a compound and all the bonds. It has nothing to do with the structure of the element. Then why INERT pair effect, which is related to the strcture of the atom, playing a role in determining stability of oxi states?
Sorry if I am bothering U too much but I am really and badly confused in this concept of effects and oxi states.
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The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
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Can marks really judge a student??
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 22:44:42 IST
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see oxidation state is nothing but the loss or gain of electrons let me make it simpler.... take out 5 electrons from Bi it will bcom Bi +5 dats it now s electrons are unwilling to go therefore it won't give the xtra 2 electrons and form Bi+3
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 22:45:07 IST
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see oxidation state is nothing but the loss or gain of electrons let me make it simpler.... take out 5 electrons from Bi it will bcom Bi +5 dats it now s electrons are unwilling to go therefore it won't give the xtra 2 electrons and form Bi+3 rate if dis hlpd ya!!!!
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 22:49:13 IST
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Thanx svj, it has cleared 80% of my doubt. Let me think myself on rest 20%, then if some problem arises, I will again ask U.
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