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![[Post New]](/templates/default/images/icon_minipost_new.gif) 28 Dec 2007 22:03:03 IST
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1.what must be the angular velocity of rotation of the earth so that the effective acceleration due to gravity at the equator is zero.the radiusof earh=64*10^4m.
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28 Dec 2007 22:08:31 IST
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g'=g-R omega square cos square@
therefore as g'=0
g=R omega square cos square@
putting the values u get
under root of g/6.4 into 10 to the power 24
plz rate is helped!!
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28 Dec 2007 22:10:00 IST
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g=g0-rw^2cosA at eq A=0 g=g0-rw^2 so calculate it further
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