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![[Post New]](/templates/default/images/icon_minipost_new.gif) 3 Jan 2008 16:53:20 IST
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when u expand a spring (horizontally) how many pairs of forces act on it?
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3 Jan 2008 16:59:18 IST
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can u elaborate your question???
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3 Jan 2008 17:00:52 IST
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i didnt understand your question clearly. but here goes: when a spring is elongated, forces act on both ends of the spring to expand it. since there are only two external forces responsible for the elongation, i think the answer is only one pair.
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3 Jan 2008 17:01:23 IST
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If you pull it slowly, then the only force acting on the spring in the stretched state will be the restoring force, which has a magnitude
kx, where k is the spring constant, and x is the elongation, ie, the extra length over the natural length of the spring.
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Will nip in at times to solve problems :)
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4 Jan 2008 08:18:41 IST
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hiii
well if u r saying k body is rested on wall.....and it is elongated by a mass on the other end...
then see to the figure
kx is the force acts on spring by wall....so acc to newton's 3rd law...= and opp force acts by spring on wall.;...
on rite hand side...
kx is the force acts of mass m by spring.......= and opp force kx on spring by mass...
x is the elongation...
L is the original length
cheers!!!!!!!!!!!
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4 Jan 2008 08:19:07 IST
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oopssssssssssss
so total 2 PAIRS of force acts
i forgot to state
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I always like to walk in rain as no one can see me crying there :(
frnds are like diamonds , if u hit them , they don't break but they slip frm ur hands
-----It is better to be hated for what you are than to be loved for what you are not.----
*****wen love and skill work together--expect a masterpiece*****
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