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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: Binomial Theorem
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sachin_gupta1991 (69)

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Q.  nCr + n-1Cr + n-2Cr + ........ rCr=
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svj29 (2140)

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i'm xtremely sorry 4 hav posted d ansr of odr questn.......sorry
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sachin_gupta1991 (69)

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The answer is n+1Cr+1.
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harsha_27 (1353)

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nCr + n-1Cr + n-2Cr +............+ n-[n-r]Cr
=coef. of x^r in [1+x]n +
coef. of x^r in [1+x]n-1 +coef. of x^r in [1+x]n-2 +..........+coef. of x^r in [1+x]n-(n-r)

=
coef. of x^r in {[1+x]n +[1+x]n-1+[1+x]n-2+........+[1+x]n-(n-r) }

=
coef. of x^r in (1+x)n { 1+1/[1+x] +1/[1+x]2 + 1/[1+x]3 +....+1/[1+x]n-r}

=
coef. of x^r in (1+x)n {( 1- 1/[1+x]n-r+1)/(1-1/[1+x])}

=
coef. of x^r in (1+x)n {( [1+x]n-r+1 -1)/(x[1+x]n-r)}

=
coef. of x^r in (1+x)n-(n-r) {([1+x]n-r+1-1)/x}

=
coef. of x^r+1 in (1+x)r{[1+x]n-r+1-1}

=
coef. of x^r+1 in (1+x)n+1-(1+x)r

=n+1Cr+1 + 0 (since max. coeff. of x in (1+x)r is r)

=
n+1Cr+1.
hope u understood......

"Nenenthedhavano naake teleedu"

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