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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jan 2008 20:51:01 IST
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Can anyone tel me how to determine the specific resistance of the wire using Post Office Box method?
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SOME SAY SKY IS THE LIMIT BUT TO ME
THERE'S SOMETHING BEYOND THE SKY
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jan 2008 20:51:37 IST
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u want the whole thing???
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its not just about hard work;its how smart you work. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jan 2008 21:05:00 IST
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yeah..i want the whole thing... i havent even heard of this b4..
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SOME SAY SKY IS THE LIMIT BUT TO ME
THERE'S SOMETHING BEYOND THE SKY
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
       
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jan 2008 21:08:29 IST
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do u know what the apparatus looks like.coz its very difficult to exlain withut the diagram
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its not just about hard work;its how smart you work. |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jan 2008 21:12:09 IST
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step 1. find the | resistance of the wire using Post Office Box method. | |  |
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it is not important where u stand, but in which direction u are moving |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jan 2008 21:15:25 IST
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this u can do by using wheatsone bridge principle :
P / Q = R / S
where, P = 1st arm resistance Q= 2nd .................... R = 3rd ................ S = 4th ..................= resistance of the wire.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jan 2008 21:19:38 IST
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shevchenko..buddy...i just dont know wat it is...i saw it first only in the IIT brochure wher the syllabus is given[/)]...
ramyani...hmm...ithe diagram isnt clear..
can u give both give any links wher this is clearly explained?
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SOME SAY SKY IS THE LIMIT BUT TO ME
THERE'S SOMETHING BEYOND THE SKY
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
       
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jan 2008 21:25:38 IST
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step 2. find the diameter of the wire ( say, d ) and length of the wire ( say, L ).
step3.
by definition,
specific resistance of the wire = S A / L ( A = area of cs )
= S d2 / 4L
Determine L = length by any scale.
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it is not important where u stand, but in which direction u are moving |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jan 2008 21:26:28 IST
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this might help http://www.goiit.com/posts/list/electricity-post-office-box-31593.htm
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"Imagination is more important than knowledge."
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jan 2008 21:29:12 IST
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specific resistance of any material is defined mathematically
as = S A / L
where S = resistance of any portion of the wire
A = its cross section
L = its length.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 14 Jan 2008 21:31:45 IST
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thnx pals!!..i think this requires a more practical learning!
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SOME SAY SKY IS THE LIMIT BUT TO ME
THERE'S SOMETHING BEYOND THE SKY
<TABLE CELLSPACING="1" CELLPADDING="1" BORDER="0">
<TR><TD>
       
<DIV ALIGN="right">Glitter Graphics</DIV></TD></TR></TABLE>
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