| Author |
Message |
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Jan 2008 20:24:11 IST
|
|
|
A long wire is bent to form a plane angle @... find the magnetic field at a point on the perpendicular bisector at a distance x from the vertex. I am not getting the HCV book answer. Moreover, why is the magnetic field inside a hollow tube zero? Any concrete logical explanation?
|
Will nip in at times to solve problems :)
|
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Jan 2008 20:39:49 IST
|
|
|
is da ans (1+sin /2)I/2pi
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Jan 2008 20:42:19 IST
|
|
|
well as for ur second question i'd say its a consequence of ampere's circuital law consider a circular loop wthin the tube passin thru the point were field is reqd. [ ] [ ] B.dl= mu *i enclosd which is zero as no i is enclosd
|
this reply: 5 points
(with 1 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Jan 2008 21:28:47 IST
|
|
|
Yeah got it... thanks elasu
|
Will nip in at times to solve problems :)
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Jan 2008 21:31:24 IST
|
|
|
is da ans 4 magn field correct. i feel i made a small mistake
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Jan 2008 21:38:13 IST
|
|
|
no.. thats wrong
|
Will nip in at times to solve problems :)
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Jan 2008 22:01:36 IST
|
|
|
well dude i got ma mistake heres da right soln let dist of the pt be d from both da lines B at the reqd pt say O , i hav written down B due 2 1 wire (its not clear in ma pic)
|
this reply: 2 points
(with 0 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Jan 2008 23:27:17 IST
|
|
|
you have considered it to be a finite wire... hmm... I took the qn as to find the magnetic field due to the long wire at the required point... as it;'ll remain long even after bending
|
Will nip in at times to solve problems :)
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Jan 2008 23:37:40 IST
|
|
|
no dude its like u r bendin a single infinitely long wire at a point itll give 2 divergent wires starting frm a point
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 16 Jan 2008 23:58:46 IST
|
|
|
yea... i get that but how have u considered the wire to be finite here/
|
Will nip in at times to solve problems :)
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Jan 2008 00:09:29 IST
|
|
|
wat do u mean i have considered the wire to be finite? in the formula basically the angles  1 and  2are the angles subtended by the endpts of the wire on the pt where field is reqd. here as one end is infin. and another finite. theta 1 is 90 and the other angles is 90- theta /. if u still think ma soln is wrong nudge me
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Jan 2008 16:19:10 IST
|
|
|
nono sorry... I made a mistake... I got the answer :)
|
Will nip in at times to solve problems :)
|
this reply: 0 points
(with 0 
in 0 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
![[Post New]](/templates/default/images/icon_minipost_new.gif) 17 Jan 2008 19:29:23 IST
|
|
|
I am answering ur second doubt. In the figure, I hav shown crosssection of a hollow wire carrying current outside the plane of screen(towards U). Consider the current as infinite no of very long current carrying wires. Hence each wire will hav its own mag field which I hav shown for 3 such wires in my firgure. U can see that none of them enters the hollow wire and hene field inside a hollow wire is zero. Hope U got it.
|
The quality of a person's life is in direct proportion to their commitment to excellence, regardless of their chosen field of endeavor.
It is during our darkest moments that we must focus to see the light.
Check out my blog at:
http://tarinbansal.blogspot.com/
Posts:
Can marks really judge a student??
Some myths about Chemical Engineering.
(A must see for every student)
Back to goiit, this time with Baby Veerappan. :D |
this reply: 2 points
(with 0 
in 1 votes ) [?]
|
|
You have to be logged on to rate
|
|
|
|
|