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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Jan 2008 17:50:48 IST
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Q.The hydrated salt Na2SO4 .nH2O undergoes 56% loss in weight on heating and becomes anhydrous.The value of "n" is? 1.5 2.7 3.4 4.10
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Write the equation and equate the molecular masses you
will surely get the answer to be 10
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Jan 2008 18:09:30 IST
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Molecular weight of Na2SO4 .NH2O =23.2 +32 +16.4+ n(2+16) =142 +18n Now since it loses 56% 0n becoming anhydrous ,therefore weight of water in the compound is 56 % = (56 /100) 142 + 18n = 18n On solving n = 10
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 19 Jan 2008 20:51:50 IST
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hey!can ya juz explain how u derived dat eq..56/100*142+18n=18?????
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