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Ask iit jee aieee pet cbse icse state board community Community Discussion Question: solve : Qs on trigonometry...
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AJ1991 (221)

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sin(+45)= - pi/4;
solve for sin

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raulrag009 (1205)

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what's the answer!!!!!!!!!!!!!
 
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sboosy (3053)

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sin(a+45)=-pi/4
expand using formula
sina+cosa=-pi/4*2^1/2
squaring
sin2a=pi^2/8 - 1
now writing sin2a as 2 sina cosa and then cosa as root of 1-sin^2a
we get fourth degree eqn in sina
solving which we get sina =root of (8+ or - pi root of 16-pi^2)/16
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