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![[Post New]](/templates/default/images/icon_minipost_new.gif) 1 Feb 2008 11:54:24 IST
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in rutherford alpha particle expt. if impact parameter(b) is 0,then angle of scattering(theta) =?
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1 Feb 2008 12:50:24 IST
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As impact parameter r  cot(@/2) thus cot(@!/2)=0 thus @/2=90 @=180
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1 Feb 2008 13:07:11 IST
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the ans is given as pi/2
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1 Feb 2008 13:10:07 IST
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then i must hav gone wrong with my formulae
it is b is proportinal to cot@
thus
@=pie/2
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1 Feb 2008 20:51:40 IST
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Hey ,just conserve momentum !! The answer got to be 180 deg !!!!!!!!!!!!
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3 Feb 2008 01:44:17 IST
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Yup its 180 deg. The collision will be head on in one dimension. The given answer is wrong...
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