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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Feb 2007 21:10:11 IST
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Hi,
If , then prove that .
How do I prove this? thanks for your time.
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Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Feb 2007 21:25:06 IST
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by the fact that sum of 2 sides of a triangle is greater than the sum of other 2 sides,
z1 , z2 , (z1+z2) will form a triangle.
therefore angle between z1 and z2 > 0 and < pi.
i.e. 0< arg(z1) - arg(z2) < pi
i.e.0< arg(z1/z2)< pi
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sachin |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Feb 2007 21:57:38 IST
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thanks! u think there is a way to prove it algebraically?
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Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 22 Feb 2007 23:58:56 IST
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plzzzzzzzzzzzzzzzzzzzzzzzzzzz. ask this question to the experts on my behalf as i have no nickles now.i will be grateful to you.also i think the information given is insufficient because the inequality given is not helpful in any way,infact what it says is obvious.so plzz. re-check ur question
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light travels the fastest ??? NO
wherever light goes it always finds that darkness has already got there |
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Feb 2007 10:14:54 IST
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yes u right. the info given is not sufficient. many others who I discussed this question with said the same thing. So lets just leave this one. I have only 2 nickles left!
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Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 23 Feb 2007 10:18:03 IST
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actually, I think the question should have been "If then prove that ."
This is true, because if you square both sides then you get
,
,
,
(the last line follows by dividing the previous line by , which is real and positive).
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Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm
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