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![[Post New]](/templates/default/images/icon_minipost_new.gif) 25 Feb 2007 19:11:31 IST
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The person who will give this ans will go into iit Q:- Establish the current distribuition over 2 resisitances R1 & R2 connected in parallel corresponds to the minimum thermal power generated in the circuit
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I always like to walk in rain as no one can see me crying there :(
frnds are like diamonds , if u hit them , they don't break but they slip frm ur hands
-----It is better to be hated for what you are than to be loved for what you are not.----
*****wen love and skill work together--expect a masterpiece*****
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25 Feb 2007 19:25:57 IST
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Hi i think the sol. is
Let R1 & R2 be the 2 resistances . thermal power generated in the circuit is
P =i^2( R1R2/R1+R2)
in parallel combination,thermal power will be minimum if:
i^2 (R1R2 / R1+R2) < i^2 (R1 + R2).......(res. in series)
or
i^2 [R1R2/R1+R2 - (R1+R2)] < 0............(1)
= i^2 [R1R2 - (R1+R2)^2/ R1+R2]
= i^2 [-(R1^2 + R2^2 + R1R2] / R1+ R2
since it is less than zero hence =n (1) satisfied
hope my ans is correct plz give me the hat
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25 Feb 2007 19:28:21 IST
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thanks vir u r cool
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I always like to walk in rain as no one can see me crying there :(
frnds are like diamonds , if u hit them , they don't break but they slip frm ur hands
-----It is better to be hated for what you are than to be loved for what you are not.----
*****wen love and skill work together--expect a masterpiece*****
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25 Feb 2007 19:29:04 IST
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now i 'i give u a desrving salute
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I always like to walk in rain as no one can see me crying there :(
frnds are like diamonds , if u hit them , they don't break but they slip frm ur hands
-----It is better to be hated for what you are than to be loved for what you are not.----
*****wen love and skill work together--expect a masterpiece*****
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25 Feb 2007 19:29:58 IST
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hey thanks
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