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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Feb 2008 18:07:55 IST
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the depression in freezing point of water for same amount of acetic acid is greater then chloroacetic acid then dichloroacetic acid why? define Kf & Kb.
2 nd why does physiorption decrease with increase of temperature.
why is reduction of metal oxide is easier if the metal formed is in liquid sate at temperature of reduction.
chlorine is electron withdrawing group but it is ortho para directing.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Feb 2008 18:11:58 IST
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help me yaar
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Feb 2008 18:13:08 IST
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1st....acetic acid associates in water(polar solvent)...hence no. of particles decreases.. however this association is greatly increased in chloroactic acid and dichloroacetic acid due to high -I effect of Cl...so association increases...and effectiv no of particles is less than in acetic acid... since m.Kf depends on no of particles, depression is max for acetic acid, then chloro- then dichloro
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Feb 2008 18:22:49 IST
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yes it's right. dude but where is other ans.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Feb 2008 18:29:58 IST
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physiorption decrease with increase of temperature because its an exothermic reaction
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Feb 2008 19:55:54 IST
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in physisorption, the adsorbate is held through weak forces. As temp increases, k.e. Of adsorbate molecules increases nd they are able break free of these weak interactions. Sneha's explanation is also correct. when a metal is melted, its entropy increases, so the change in entropy upon reduction of oxide also increases (refer ellingham diagram). So delta S increases, and delta G decreases, nd reduction becomes easier
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 26 Feb 2008 20:06:42 IST
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for Cl, -I > +R, so it is deactivating. However, its +R effect operates in o and p positions, so a sigma complex there will not be as unstable as it would be in m position i.e. In m position only -I so highly unstable, in o and p position -I and +R so less unstable, even though inductive is dominating.
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![[Post New]](/templates/default/images/icon_minipost_new.gif) 27 Feb 2008 17:39:25 IST
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yaar help me out.
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