is the answer 8, 8 and1...

this is one method.....

for it to be a limiting case let us concider an eqn. in whos graph, f(1)=1, f(0)=1 and  consequently f(1/2)= -1

substituting it in the eqn.s for ax2+bx+c we get 3 eqn.s solving which we have

a=8,b=-8 and c=1

moda=8, modb=8, mod c=1

 

or

 

we can imagine of another eqn. in which we have f(1)=-1, f(0)= -1 and consequently f(0)=1

following the same procedure for this eqn. we obtain a= -8 b=8 and c= -1

but again moda=8 modb=8 and modc=1

 

rate if useful

then what is the correct answer.....

im eager to know about.....

not worried abt the correct answer  yaar i jus wanna know whether my funda applied is correct or not......silly mistake bhi ho sakta hai but what i want to know is whether the method was right.....cud u post the soln in detail if u have it???? if no then plz invite some one else like hsbhatt sir to come and have a look at this one.....

I had seen a question that went:

 

The solution goes:

 

Then