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![[Post New]](/templates/default/images/icon_minipost_new.gif) 9 Mar 2008 13:45:38 IST
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In an isosceles triangle ABC,AB=AC.If vertical angle A is 20o ,then a3+b3 is equal to
(a)3a2b (b)3b2c
(c)3c2a (d)abc
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9 Mar 2008 18:53:24 IST
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wats d ansr yaar
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9 Mar 2008 18:55:34 IST
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i donno :(
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9 Mar 2008 23:01:14 IST
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.
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 . Also  . So,  (b = c as it is an isosceles triangle) Correct option is (C).
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Guide to latex:
http://www.goiit.com/posts/list/community-shelf-a-guide-to-latex-48056.htm
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10 Mar 2008 06:41:16 IST
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apply sine rule a=2bcos80 now a^3+b^3= b^3[1+8cos^380] =b^3[1+2cos240+6cos80] now cos 240 =-1/2 and cos 80 =a/2b n u get a^3+b^3 = 3ac^2 edit: guess i was typin my soln wen koni 2 ws doin it
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