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![[Post New]](/templates/default/images/icon_minipost_new.gif) 13 Mar 2008 18:33:12 IST
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find
1. [n ] [ ] sin ( [ ] (n2 + n))
2. [n ][] cos ([ ] (n2 + n))
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JEE and OLYMPIA INFINATUM
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13 Mar 2008 18:36:14 IST
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can u type the question again .............
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13 Mar 2008 18:40:46 IST
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sorry guys..
its
1. lim [n --> infinity] sin (pi. sqrt(n2+ n))
1. lim [n --> infinity] cos (pi .sqrt(n2+ n))
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13 Mar 2008 18:46:50 IST
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edited
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Nitwit Blubber Odment Tweak
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13 Mar 2008 18:47:06 IST
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edited
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13 Mar 2008 18:48:13 IST
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nope...
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13 Mar 2008 18:48:52 IST
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EDITED... im sorry.. whoever saw this post, i had written the wrong stuff!
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13 Mar 2008 18:52:32 IST
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eh??
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13 Mar 2008 18:53:27 IST
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sorry man.. i got confused.. 1st answer is NOT 0..
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13 Mar 2008 18:54:43 IST
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edited
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13 Mar 2008 18:56:15 IST
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wat dyu mean 2nd is -1/2 or 1??
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13 Mar 2008 18:57:47 IST
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edited
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13 Mar 2008 19:00:09 IST
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nope.. both answers wrong..
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13 Mar 2008 19:05:05 IST
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sorry found my mistake..
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13 Mar 2008 21:54:59 IST
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hint: use binomial for root (n^2 + n)
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